4^(x+1)=4^2x+4

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Solution for 4^(x+1)=4^2x+4 equation: 



4^(x+1)=4^2x+4

We move all terms to the left:

4^(x+1)-(4^2x+4)=0

We get rid of parentheses

4^(x+1)-4^2x-4=0

We move all terms containing x to the left, all other terms to the right

4^(x+1)-4^2x=4

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